\(\frac{{dy}}{{dx}} = \frac{{dy}}{{du}} \times \frac{{du}}{{dx}}\) \(\frac{{dy}}{{dx}} = \frac{1}{2}{(u)^{ - \frac{1}{2}}} \times (4x + 3)\) \(\frac{{dy}}{{dx ...

This is made possible by exploiting a key mathematical property that applies to sensitivities called the chain rule of differentiation, which links the derivatives of parts of a function to the ...