What does the symbol nabla indicate? - Mathematics Stack …
2018年3月27日 · The nabla can be applied to a number of different areas in multivariable calculus, such as divergence or curl. In all these cases, the nabla can be treated like a vector …
what does $(A\\cdot\\nabla)B$ mean? - Mathematics Stack …
Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their …
Proving $d^\\nabla( d^\\nabla \\omega) = F^\\nabla \\wedge …
2024年2月19日 · What I said above answers your question. But here are some extra good-to-know things. In Riemannian geometry, it is often the case that people do not go higher than …
multivariable calculus - Del. $\partial, \delta, \nabla $: Correct ...
$\nabla$: Called Nabla or del. This has four different uses, which can be easily distinguished while reading out loud, but it gets confusing when the first and last uses (grad and covariant …
Why does $\\nabla \\to ik$ when you Fourier transform?
I am reading a text that describes the scattering of light by a particle with dielectric constant $\\epsilon$ After a bit of maths starting from Maxwell's equations they obtain: $$\\nabla …
How do we pronounce this symbol: $\\nabla \\phi$
2014年5月12日 · $\begingroup$ @Jean-Claude Arbaut: nabla is a name of “∇” symbol (cf. equals sign – “=”, times sign – “×”). Del is a name of the operator in vector analysis. The thing with …
What is $\\nabla$ $\\vec{F}$? - Mathematics Stack Exchange
"Nabla" $\nabla$ is a vector. You can do inner or outer products with vectors. Divergence is dot product (inner product) with a vector.
calculus - Difference between $\nabla T$ and $\nabla \cdot E ...
2015年4月27日 · The notation $\vec{\triangledown} \cdot \vec{E}$ is taking a bit of a liberty with the mathematical 'del' operator and the dot product operation.
What is the meaning of $A. \\nabla - Mathematics Stack Exchange
2018年7月21日 · If $\mathbf A = \pmatrix{a_x\\a_y\\a_z}$, then $$(\mathbf A\cdot\nabla)\phi = a_x\frac{\partial}{\partial x}\phi + a_y\frac{\partial}{\partial y}\phi + a_z\frac{\partial}{\partial …
Can the Laplacian be thought of as $ \\nabla^{\\dagger} \\nabla
2016年9月27日 · My first thought: Perhaps if we thought of $ \left | \psi \right \rangle $ as a vector of infinitely many components, and each element of the vector-operator $ \nabla $ as a matrix …